Propane reacts with chlorine in sunlight to give two products, 1-chloropropane is obtained in 44% yield and 2-chloropropane is obtained in 56% yield of the total product 2-methylpropane reacts with chlorine under same conditions to produce 1-chloro-2methylpropane 66% and 2-chloro-2-methylpropane 33%. The percent yield (X) of the major monochloro product obtained when 3-ethylpentane is treated with $C l_{2}$ in similar conditions. The percent yield of the monochloro product obtained in minimum amount is (Y). Total number of different type of carbonyl compounds formed (Z) during ozonolysis of mixture of all the benzene derivatives of formula $C_{8} H_{10}$ .Choose the correct options.
(Answer rounded off to nearest integer)

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Z=12

X+Y+Z=79

Y=12

X=63

answer is A, B, D.

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Detailed Solution

$C H_{3} - C H_{2} - C H_{3}$
It has 6 primary H =44% given product and 2 secondary H=56% given product.
So $\frac{44}{6} = 7.33; \frac{28.0}{7.33} = \frac{3.82}{1} = \frac{r e a c t i v i t y w i t h 2^{o} H}{r e a c t i v i t y w i t h 1^{o} H}$
In Question Image

It has 9 primary H=66% given product
It has 1 tertiary H=33% given product
So $\frac{66}{9} = 7.33; \frac{33}{7.33} = \frac{4.5}{1} = \frac{r e a c t i v i t y w i t h 3^{o} H}{r e a c t i v i t y w i t h 1^{o} H}$
$\frac{33}{1} = 33$
$∴$ Reactivity ratio for monochlorination with
$1^{o} H : 2^{o} H : 3^{o} H = 1 : 3.82 : 45$