Propene $C H_{3} - C H = C H_{2}$ can be converted to 1-propanol by oxidation. Which set of reagents among the following is ideal to effect the conversion?

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$\frac{O_{3}}{Z n}$ dust

$\frac{O s O_{4}}{C H_{4}, C l_{2}}$

$B_{2} H_{6}$ and alkaline $H_{2} O_{2}$

Alkaline $K M n O_{4}$

answer is B.

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Detailed Solution

In the Conversion of propene to 1-propanol by oxidation the reagent used is $B_{2} H_{6}$ and alkaline $H_{2} O_{2}$ ,this reaction is also called hydroboration-oxidation reaction. During hydroboration-oxidation of alkenes addition of water to the double bond takes place in anti-Markownikoff fashion. Since negative part of water attached to higher number of hydrogen of carbon atom of unsymmetrical alkenes.

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