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Propene on treatment with chlorine at $500 - 600^{0} C$ gives the following product (s) :

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${CH}_{3} - CH = CH - Cl$

All the above

$Cl - {CH}_{2} - CH = {CH}_{2}$

answer is C.

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Detailed Solution

Propene on treatment with chlorine at $500 - 600^{0} C$ produces allyl chloride. The reaction takes place as follows :

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