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Propene when heated with chlorine at about 500° C forms

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All the three

${CH}_{3} {CHClCH}_{2} Cl$

${CH}_{2} ClCH = {CH}_{2}$

${CH}_{2} ClCHCl {CH}_{2} Cl$

answer is A.

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Detailed Solution

${CH}_{3} - CH = {CH}_{2} + {Cl}_{2} \overset{500 {}^{0}C}{\to} {ClCH}_{2} CH = {CH}_{2} + HCl$

This reaction is called allylic halogenation reaction because halogenation

occurs at the allylic position of an alkene.

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