Properties such as boiling point, freezing point and vapour pressure of a Pure solvent change when solute molecules are added to get Homogeneous solution. These are called colligative properties, Applications of colligative properties are very useful in day- to day life. One of its examples is the use of ethylene glycol and water mixture as Anti-freezing liquid in the radiator of autombiles A solution M is prepared by mixing ethanol and water. The mole Fraction of ethanol in the mixture is 0.9 Given the freezing point depression constant of water Freezing point depression constant of ethanol = Boiling point elevation constant of water= Boiling point elevation constant ethanol Standard freezing point of water=273K Standard freezing point of ethanol = 155.7 K Standard boiling point of water= 373K Standard boiling point of ethanol= 351.5 K Vapour pressure of pure water= 32.8 mm Hg Vapour pressure of pure ethanol= 40 mm Hg Molecular weight of water= Molecular weight of ethanol= In answering the following questions consider the solution to be ideal dilute solutions and Solutes to be non-volatile and non-dissociative
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Properties such as boiling point, freezing point and vapour pressure of a Pure solvent change when solute molecules are added to getHomogeneous solution. These are called colligative properties, Applications of colligative properties are very useful in day- to day life.One of its examples is the use of ethylene glycol and water mixture as Anti-freezing liquid in the radiator of autombiles A solution M is prepared by mixing ethanol and water. The mole Fraction of ethanol in the mixture is 0.9 Given the freezing point depression constant of water (Kf water=1.86K kgmol−1)Freezing point depression constant of ethanol = Kf ethanol=2.0K Kgmol−1Boiling point elevation constant of water= Kbwater=0.52K Kgmol−1Boiling point elevation constant ethanol =Kbethanol=1.2KKgmol−1Standard freezing point of water=273KStandard freezing point of ethanol = 155.7 KStandard boiling point of water= 373KStandard boiling point of ethanol= 351.5 KVapour pressure of pure water= 32.8 mm HgVapour pressure of pure ethanol= 40 mm HgMolecular weight of water= 18gmol−1Molecular weight of ethanol= 46 g mol−1In answering the following questions consider the solution to be ideal dilute solutions and Solutes to be non-volatile and non-dissociative