Q.

Proton moving in a perpendicular magnetic field 'B' possesses kinetic energy 'K'. If the magnetic field increases to '4B' and the particle is constrained to move in the path of same radius, the kinetic energy will be

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a

8K

b

4K

c

K

d

16K

answer is D.

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Detailed Solution

r=mvqB=2mE2qB E  B2 If B increases 4 times E becomes to 16 times 

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Proton moving in a perpendicular magnetic field 'B' possesses kinetic energy 'K'. If the magnetic field increases to '4B' and the particle is constrained to move in the path of same radius, the kinetic energy will be