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Q.

Prove that i) nCr1+nCr=n+1Cr

ii) Prove that nCr2+2.nCr1+nCr=n+2Cr

iii) For 3rn. Prove that n1Cr+3(n3Cr1)+3(n3Cr2)+n3Cr3

see full answer

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Detailed Solution

i) L HS nCr1+nCr

=n!(nr+1)!(r1)!+n!(nr)!r!

=n!1(nr+1)!(r1)!+1(nr)!(r1)!

=n!(nr)!(r1)!1nr+1+1r

=n!(nr)!(r1)!r+nr+1(nr+1)r

=n!(nr)!(r1)!n+1(nr+1)r

=(n+1)!(nr+1)!r!=n+1Cr=RHS

 

LHS=nCr2+2.nCr1+nCr

= nCr2+nCr1+ nCr1+nCr

=n+1Cr1+n+1Cr=n+2Cr

 nCr+nCr1=n+1Cr

 n3Cr+3(n3Cr1)+3(n3Cr2)+n3Cr3

= n3Cr+n3Cr1+2(n3Cr1+n3Cr2)+ n3Cr2+n3Cr3

 nCr+nCr1=n+1Cr

=n2Cr+2(n2Cr1)+n2Cr2

= n2Cr+n2Cr1+ n2Cr1+n2Cr2

=n1Cr+n1Cr1=nCr

 

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