Q.

Prove that: 1-cosA1+cosA  = π‘π‘œπ‘ π‘’π‘ 𝐴 βˆ’ π‘π‘œπ‘‘π΄.

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Detailed Solution

We have to prove whether LHS is equal to RHS or not.
𝐿𝐻𝑆 =1-cosA1+cosA


Multiplying LHS by 1-cosA1-cosA
 

β‡’ 𝐿𝐻𝑆 = 1-cosA1+cosA Γ— 1-cosA1-cosA
 

β‡’ 𝐿𝐻S = (1-cosA)21+cosAΓ—1-cosA
β‡’ 𝐿𝐻𝑆 = 1-cosA1-cos2A
As 𝑠𝑖𝑛2𝐴 + π‘π‘œπ‘ 2𝐴 = 1
β‡’ 1 βˆ’ π‘π‘œπ‘ 2𝐴 = 𝑠𝑖𝑛2𝐴
Putting this in LHS, we get
β‡’ 𝐿𝐻𝑆 = 1-cosAsinA

β‡’ 𝐿𝐻𝑆 =    1sinA-cosAsinA
β‡’ 𝐿𝐻𝑆 = π‘π‘œπ‘ π‘’π‘ 𝐴 βˆ’ π‘π‘œπ‘‘ 𝐴
β‡’ 𝐿𝐻𝑆 = 𝑅𝐻𝑆
Hence, proved.
 

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