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Q.

Pure Benzene freezes at 5.4 °C. A solution of0.223 g of phenyl acetic acid C6H5CH2COOH in 4.4 g of benzene Kf=5.12 K kg mol-1 freezes at 4.47 °C. From this observation, one can conclude that

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a

phenyl acetic acid exists as such in benzene

b

phenyl acetic acid undergoes partial ionization in benzene

c

phenyl acetic acid undergoes complete ionization in benzene

d

phenyl acetic acid dimerizes in benzene.

answer is D.

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Detailed Solution

m=-ΔTfKf=(5.4-4.47)5.12 mol kg-1 i.e. 0.223 g/M(4.4/1000)kg=0.935.12 mol kg-1

Solving for M, we get M=279 g mol-1

Number of molecules of phenyl acetic acid =279136=2

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