Pure nitrosyl chloride $(N O C l)$ gas was heated to $240^{0} C$ in a $0.1 L$ container. At equlilibrium the total pressure was 1.0 atm and $N O C l$ pressure was 0.64 atm. The value of $K_{p} i s 16.875 \times 10^{- x}$ atm then x is

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At eqm p-2x
$\begin{array}{l} p + x = 1; p - 2 x = 0.64, x = 0.12 \\ K_{p} = \frac{{(0.24)}^{2} (0.12)}{{(0.64)}^{2}} \\ = 16.875 \times 10^{- 3} a t m \end{array}$

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