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+Q charge is present at the points A, B, C of a triangle having equal limbs. The intensity of electric field at O will be :

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$\frac{1}{4 {πe}_{0}} \frac{Q}{r^{2}}$

$\frac{1}{4 {πe}_{0}} \frac{Q}{r}$

Zero

$\frac{1}{4 {πe}_{0}} \frac{Q^{2}}{r^{2}}$

answer is C.

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Detailed Solution

Electric field due each each charge will make same angle with each other such that N x $θ$ = 360⁰hence the resultant electric field is zero.

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