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Q.

Quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals as shown below.


Question Image

 Find the value of x if JF = 8x + 4 and EG = 24x – 8.


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a

2

b

4

c

6

d

8 

answer is A.

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Detailed Solution

Given, quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals.
Question ImageWe know that a rectangle is a parallelogram in which the angles are at 90 .
Also, both of its diagonals are equal and bisect each other.
On the basis of this property, we can say that in the rectangle EFGH,
JF=EJ=JG
Next, from the given diagram, we have,
EG=EJ+JG EG=JF+JF EG=2JF Substituting the values of EG and JF, as 24x – 8 and 8x + 4 respectively, we get,
24x8=2(8x+4)
Now, we will solve this equation for the value of x as follows,
24x8=16x+8 24x16x=8+8 8x=16 x= 16 8 x=2
So, the value of x is obtained as 2.
Hence, the correct option is (1).
 
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Quadrilateral EFGH is a rectangle in which J is the point of intersection of the diagonals as shown below. Find the value of x if JF = 8x + 4 and EG = 24x – 8.