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Q.

A gas expands against a constant external pressure of 2.00 atm, increasing its volume by 3.40 L. Simultaneously, the system absorbs 400 J of heat from its surroundings. What is ∆E, in joules, for this gas ?

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Detailed Solution

Given, P = 2.00 atm,

∆V=3.4 L q=400 J Work done by gas w = -P∆V = -2 × 3.4 =-6.8 L atm =-6.8 × 101.32 J =-688.976 J ∆E=q+-w =400+-688.976 =-288.976 ≈-289 J

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A gas expands against a constant external pressure of 2.00 atm, increasing its volume by 3.40 L. Simultaneously, the system absorbs 400 J of heat from its surroundings. What is ∆E, in joules, for this gas ?