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Q.

In the reaction : Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H 2O, the oxidation state of lead changes from

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a

+2 to zero

b

+2 to +4

c

+4 to +2

d

+4 to zero

answer is C.

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Detailed Solution

Pb3O4 is a mixed oxide. It exist as PbO2.2PbO
Pb3O4+ 8HCl → 3PbCl2 + Cl2 + 4H2O
This reaction can be split into
A) 

large mathop {2PbO}limits^{ + 2} ; + ;4HCl; to ;mathop {2PbC{l_2}}limits^{ + 2} ; + ;2{H_2}O


B) 

large mathop {Pb{O_2}}limits^{ + 4} ; + ;4HCl; to ;mathop {PbC{l_2}}limits^{ + 2} ; + ;C{l_2}; + ;2{H_2}O


Oxidation state of Pb changes from +4 to +2

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In the reaction : Pb3O4 + 8HCl → 3PbCl2 + Cl2 + 4H 2O, the oxidation state of lead changes from