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Q.

pK_a of lactic acid
is 5. pH of 0.005 M calcium lactate solution is

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a

10.5

b

8.5

c

5.0

d

9.7

answer is B.

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Detailed Solution

$0 .005 M {calcium lactate [(Lactate)}_{2} Ca] ∴ [Lactate] = 0 .01 M pH = 7 \frac{{pK}_{a}}{2} + \frac{\log C}{2} = 7 + 2 .5 - 1 = 8 .5$

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