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The (C − H) bond length order in hydro-carbons in which the hybridization of carbon is ${sp}^{3} or {sp}^{2} or sp$

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$sp - s > {sp}^{2} - s > {sp}^{3} - s$

$sp - s = {sp}^{2} - s = {sp}^{3} - s$

${sp}^{3} - s > {sp}^{2} - s > sp - s$

${sp}^{3} - s > sp - s > {sp}^{2} - s$

answer is C.

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Detailed Solution

${sp}^{3} - s (1.09 A °) > {sp}^{2} - s (1.08 A °) > sp - s (1.06 A °)$

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