The density of copper is 8 gm/cc. Number of coulombs required to plate an area of 10 cm × 10 cm on both sides to a thickness of 10^–2cm using ${\mathrm{CuSO}}_4$solution as electrolyte is

$$\begin{gathered} \mathrm{Copper} \mathrm{density} =8 \mathrm{g}/{\mathrm{cm}}^3 \\ \mathrm{Vol}. = \mathrm{A}\times \mathrm{t} = {10}^2\times {10}^{-2} =1 \\ \mathrm{Total} \mathrm{Vol}. = 2 \mathrm{CC} \\ 1\mathrm{CC} \mathrm{Vol}. = 8\mathrm{gm} \mathrm{of} \mathrm{Cu} \\ \mathrm{weight} \mathrm{of} \mathrm{copper} \mathrm{for} 2 \mathrm{CC} = 8\times 2=16\mathrm{gm} \\ {\mathrm{Cu}}^{2+}+2{\mathrm{e}}^{-}\to \mathrm{Cu} \\ 96500\mathrm{C} = 32\mathrm{gm} \mathrm{of} \mathrm{Cu} \\ \mathrm{and} \mathrm{for} \mathrm{the} 16\mathrm{gm} =\frac{96500}{2}=48250 \end{gathered}$$

Therefore, the correct option is A