Q.

A quadratic polynomial, whose zeroes are –3 and 4, is

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a

 x²  x + 12  

b

x² + x + 12

c

(x²/2)  (x/2)  6 

d

2x² + 2x  24

answer is C.

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Detailed Solution

Let the given zeros be α = -3 and β = 4. 

Sum of zeroes, α + β= -3 + 4 = 1  

Product of Zeroes, αβ = -3 × 4 = -12  

Therefore, the quadratic polynomial = x² – (sum of zeroes)x + (product of zeroes)  

= x² – (α + β)x + (αβ)  

= x² – (1)x + (-12)  

= x² – x – 12 

Dividing by 2, 

= (x²/2) – (x/2) – 6

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