$R-CON{H}_2\stackrel{B{r}_2+NaOH}{\to }$$R-N{H}_2$, the number of moles of $NaOH$ required for every two moles of amide in the net reaction will be 

In Half man degradation reaction each made of Amide requires 4 moles of so the number of moles for 2 moles of Amide is ‘8’

In Hoffman's degradation reaction, reaction of bromine with sodium hydroxide leads to the formation of sodium hypobromite (NaOBr) which in turn transforms the primary amide into an isocyanate intermediate. In the reaction, four moles of NaOH and one mole of Bromine are used to produce one mole of amine, hence for 2 moles of amine, 8 moles of NaOH is required.