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R is a relation from {11, 12, 13} to {8, 10, 12} defined by y = x–3. Then R^–1 is

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{(8, 11), (10, 13)}

{(11, 8), (13, 10)}

{(10, 13), (8, 11)}

{(11, 8), (10, 13), (12, 15)}

answer is A.

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Detailed Solution

$R = {(11, 8), (13, 10)} R^{- 1} = {(8, 11), (10, 13)}$

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