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R is a relation from ${11, 12, 13} to {8, 10, 12}$ defined by y = x - 3 then R^-1 is

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${(11, 8), (13, 10)}$

${(11, 8), (10, 13), (12, 15)}$

${(8, 11), (10, 13)}$

${(10, 13), (8, 11)}$

answer is A.

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Detailed Solution

A={11,12,13},B={8,10,12}

$R : A \Rightarrow B, y = x - 3 ∴ R = \{(11, 8), (13, 10)\} \Rightarrow R^{- 1} = \{(8, 11), (10, 13)\}$

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