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Radiations of wavelength 400 Nm incidents on a photo sensitive material of work function 2.2 eV the stopping potential is nearly

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0.1V

0.4V

0.5V

0.9V

answer is D.

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Detailed Solution

$E = w_{0} + e v_{0} \Rightarrow \frac{1240}{λ (n m)} e v = w_{0} + e v_{0}$

$v_{0} = 0.9 v$

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