Radioactive decay follows first order kinetics. Consider the following radioactive decay in a 45 L closed vessel at 300 K.B 83 i211→ Tl 207 81 +He 4 2 The reaction starts with 4 mol of Bi 211 83 . The pressure (in atm) developed after 20.4 minutes from the start is_____. [Given t12=5.1min; Use ln2 = 0.7, R = 0.08 L atm mol-1 K-1]

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Radioactive decay follows first order kinetics. Consider the following radioactive decay in a 45 L closed vessel at 300 K.
${}_{83}B i^{211} \overset{}{\to} {}_{81}{Tl}^{207} + {}_{2}{He}^{4}$
The reaction starts with 4 mol of ${}_{83}{Bi}^{211}$ . The pressure (in atm) developed after 20.4 minutes from the start is_____. [Given $t_{\frac{1}{2}} = 5.1 \min$ ; Use ln2 = 0.7, R = 0.08 L atm $m o l^{- 1} K^{- 1}]$

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In 20.4 min (4 half-lives) 3.75 moles of Bi would have been disintegrated to give same number of moles of He.

$p = \frac{3.75 \times 0.08 \times 300}{45} = 2 a t m$

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