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Radius of 3rd Bohr orbit is

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$6.529 \overset{\circ}{A}$

$2.116 \overset{\circ}{A}$

$4.761 \overset{\circ}{A}$

$8.464 \overset{°}{A}$

answer is C.

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Detailed Solution

$r = 0.529 n^{2} A^{o} = 0.529 {(3)}^{2} A^{o} = 4.761 A^{o}$

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