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Q.

Radius of curvature of human eye is 0.78 cm For an object at infinity, image is formed at 3 cm behind the refracting surface. The refractive index of eye is

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a

1

b

6.2

c

3

d

1.35

answer is A.

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Detailed Solution

μ2v-μ1u=μ2-μ1R
Putting v = 3 cm
μ1=1u=
u = 0.78cm
μ231=μ210.78μ2=1.35

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