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Q.

Radius of curvature of one surface of double convex lens is three times of the other. If focal length of the lens is 30 cm and refractive index of the lens material is3/2, then radius of curvature are

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a

60 cm

b

80 cm

c

40 cm

d

20 cm

answer is A.

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Detailed Solution

R1=3R,R2=−R,f=30cm,μ=32

Question Image

 

 

 

 

1f=(μ−1)1R1−1R2

130=32−113R+1R

130=12×1+33R=12×43R⇒130=23R

R=20

 Since R2=20cm,R1=3R=3(20)=60cm

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