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Q.

Radius of earth is around 6000 km. The weight of body at height of 6000 km from earth surface becomes

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a

Half

b

One-fourth

c

One third

d

No change

answer is B.

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Detailed Solution

$g' = g {(\frac{R}{R + h})}^{2}$ $\Rightarrow$ when $h = R$ then $g' = \frac{g}{4}$
So the weight of the body at this height will become one-fourth.

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