Radius of the nucleus of the atom with A=216 is (R0 =1.3fm)

R=ROA1/3=1.3×(216)1/3=1.3×6=7.8fm

R=ROA1/3=1.3×(216)1/3=1.3×6=7.8fm

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Radius of the nucleus of the atom with A=216 is (R₀ =1.3fm)

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7.2fm

7.8 fm

280 fm

19 fm

answer is B.

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$R = R_{O} A^{1 / 3} = 1.3 \times (216)^{1 / 3} = 1.3 \times 6 = 7.8 fm$

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