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Radius of third orbit of $L i^{+ 2}$ is ‘x’ cm then debroglie wavelength of electron in the first orbit of $L i^{+ 2}$ is

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$\frac{2 π x}{9}$

$\frac{2 π x}{6}$

$3 π x$

$\frac{2 π x}{3}$

answer is A.

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Detailed Solution

DE Broglie wavelength = $λ = \frac{2 π r}{n}$
$r_{3} = r_{1} X \frac{3^{2}}{3}$

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