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Rahul Dravid wants to wear 6.023 × 10²¹ “Ag” atoms in the form of a ring. His ‘Silver-Gold-Copper’ alloy ring consists of 20% of Silver. The mass of the ring is 0.9x. What is ‘x’?

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Detailed Solution

6.023 × 10²³ atoms Ag – 108g
6.023 × 1023 atoms Ag – 1.08g
20g Ag – 100g Ag – Au Alloy
1.08g Ag = $\frac{1 .08 \times 100}{20} = 5 .4 g$
0.9x = 5.4 $\Rightarrow$ x = 6

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