Railway lines are laid with gaps to allow for expansion. If the gap between the steel rails 66m long be 3.63 cm at $10^{0} C$ , then the temperature $({}^{0}C)$ at which the lines touch (coefficient of linear expansion for steel $= 11 \times 10^{- 6} {}^{0}C^{- 1})$ is

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answer is 60.

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Detailed Solution

$e = L_{0} α (∆ θ) e = 3.6 cm = 3.63 \times 10^{- 2} m L_{0} = 66 m; α = 11 \times 10^{- 6} / {}^{0}C ∆ θ = {(θ - 10)}^{0} C = 3.63 \times 10^{- 2} = 66 \times 11 \times 10^{- 6} (θ - 10) On solving θ = 60^{0}$

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