Rain is falling down vertically. To a man walking on the road, velocity of rain appears to be 1.5 times his velocity. Then to protect himself from rain, he holds his umbrella at an angle $θ$ to the vertical such that tan $θ$ =

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$\frac{2}{\sqrt{5}}$

$\frac{\sqrt{5}}{2}$

$\frac{2}{3}$

$\frac{3}{2}$

answer is B.

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Detailed Solution

$sinθ = \frac{velocity of man}{Velocity of rain w . r . t man} = \frac{V}{1.5 V} = \frac{2}{3}$
$cosθ = \frac{\sqrt{5}}{3}, Tanθ = \frac{2}{\sqrt{5}}$

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