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Rajan got married 8 years ago. His present age is $\frac{6}{5}$ times his age at the time of his marriage. Rajan’s sister was 10 years younger to him at the time of his marriage. The age of Rajan’s sister is

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36 years

40 years

38 years

32 years

answer is C.

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Detailed Solution

Let Rajan's sisters present age is $x$ years

Hence, the Rajan preaent age is $x + 10$

Rajan age at the time of his marriage was $x + 10 - 8 = x + 2$

Given that

$\begin{array}{rcl} \frac{6}{5} (x + 2) & = & (x + 10) \\ 6 x + 12 & = & 5 x + 50 \\ x & = & 38 \end{array}$

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