Ramesh, an ice cream seller, uses the container shown in the given figure to freeze ice creams. He gets an order for 700 ice creams. The density of ice is 0.9167 g/cm³. What quantity of ice cream should he freeze in order to complete the order?

It can be seen that the given container consists of a cone and a cylinder.

Given: Radius of the cylinder (r) = 2 cm

Height of the cylinder (h₁) = 10 - 3 = 7 cm

Radius of the cone (r) = 2 cm

Height of the cone (h₂) = 3 cm

∴ Volume of one ice cream in the container

$={\mathrm{\pi r}}^2{\mathrm{h}}_1+\frac{1}{3}{\mathrm{\pi r}}^2{\mathrm{h}}_2$

$=\frac{22}{7}\times 2^2\times 7+\frac{1}{3}\times \frac{22}{7}\times 2^2\times 3$

$=88+\frac{88}{7}$

$=\frac{704}{7} {\mathrm{cm}}^3$

The total number of ordered ice cream is 700.

Therefore, the volume of ice cream to be frozen for completing the order

$=700\times \frac{704}{7}$

$=70400 {\mathrm{cm}}^3$
Therefore, the total quantity of ice cream to be frozen

= Density of ice cream × Total volume of the ice cream

= 0.9167 × 70400 cm³

= 64535.68 g

≈ 64.5 kg