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Q.

Range of  sin1xcos1x  is

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a

[3π2,π2]

b

[5π3,π3]

c

[0,π]

d

[3π2,π]

answer is A.

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Detailed Solution

Sin1xCos1x=π2cos1xcos1x =π22cos1x  W.K.T. 0Cos1xπ   02Cos1x2π  2π2Cos1x0 π22ππ22Cos1xπ 2 3π2π22Cos1xπ2

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