Q.

Range of sin-1x+cos-1x+tan-1x is

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a

0,π2

b

π4,3π4

c

0, p

answer is B.

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Detailed Solution

sin1(x) is defined in x[1,1] cos1(x) is defined in x[1,1] tan1(x) is defined in x(,+)  So f(x)=sin1(x)+cos1(x)+tan1(x) is defined in x[1,1] Sof(x)=π2+tan1(x) Nowf(x)=11+x2>0x[1,1]  So f(1)=π2+tan1(1)=π2π4=π4  and f(+1)=π2+tan1(1)=π2+π4=3π4 Sof(x)π4,3π4

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