Rate constant for a chemical reaction taking place at 500K is expressed as $k = A . e^{- 1000}$ . The activation energy of the reaction is____kcal/mol.

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answer is 1000.

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Detailed Solution

$k = A \cdot e^{- E_{a} / R T}$
given $k = A . e^{- 1000} \frac{E_{a}}{RT} = 1000 E_{a} = 1000 \times 2 \times 10^{- 3} (500) = 1000 \times 10^{- 3} (1000)$
$= 1000 K . Cal$

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