Rate constant ‘K’ varies with temperature by equation. log$\log K\left(mi{n}^{-1}\right)=5-\frac{\left(2000\right)}{T}$. We can conclude that $\left(\mathrm{R}=8.314\mathrm{J} {\mathrm{Mol}}^{-1}{\mathrm{K}}^{-1}\right)$