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Q.

Rate law for 2A+BC+D from following data : 
 

S.No[A] (M)[B] (M)Rate (M/s)
10.010.012.5
20.010.025
30.030.0245

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a

r=K[A]2/3[B]1/3

b

r=K[A][B]1/3

c

r=K[A]1/3[B]

d

r=K[A]2[B]

answer is B.

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Detailed Solution

detailed_solution_thumbnail

From the given data, Let Initial rate=2.5

If [B]=doubled Rate= doubled=2(2.5)=5

If [A]=tripled Rate becomes 32 times =32(2.5)

Rate law=KA2B

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