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Q.

Rate of SN2 will be negligible in :

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a

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b

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c

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d

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answer is C.

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Detailed Solution

  • In an SN2 reaction, the nucleophile has to approach the central carbon from the side, opposite to the leaving group (here: bromide). 
  • This approach is more difficult, as the number of alkyl substituents the central carbon carries increases. 
  • A tertiary carbon is the most sterically hindered when compared to a secondary and a primary carbon, therefore, the rate of SN2 will be negligible when the leaving group is connected to a tertiary carbon.
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