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Q.

Ratio of coefficients of x18y2 and x17y3 in the expansion of 2x3+3y220 is mn(where m and n are natural numbers and in simplest form), then m+n is

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answer is 29.

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Detailed Solution

General term Tr+1=20Cr2x320r3y2r
Tr+1=20Cr23202rx20ryr...............(1)
Put r=2in(1)
T3=20C22316.x18.y2
coefficient of x18y12 is =20C22316
Put r=3   in(1)
T4=20C32314x17y3
coefficient of x17y3 is 20C3(23)14
Reqd. ratio = 20C22316 20C32314=16×232
=227

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