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Ratio of hybrid and unhybrid orbitals taking part in bond formation in ethylene molecule

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1:1

2:3

3:4

1:2

answer is A.

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Detailed Solution

In ethylene $(H_{2} C = {CH}_{2})$ , each carbon under goes sp² hybridization.

each carbon consists of 3 hybrid orbitals and one pure(unhybrid) p-orbital are present and each hydrogen consists of one s-orbital.

Ratio of hybrid and unhybrid orbitals = 6:6=1:1

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