Ratio of total intensity of magnetic field at equator to poles is

${\mathrm{B}}_{\mathrm{H}}=\mathrm{Bcos}\mathrm{\theta }$
${\mathrm{B}}_{\mathrm{V}}=\mathrm{Bsin}\mathrm{\delta }$
At equator, $\mathrm{\delta }=0^{\circ }$
So, B_H = B, B_v = 90°
At poles, $\mathrm{\delta }={90}^{\circ }$
So, B_H=B, B_v = B
So, the ratio of total intensity of magnetic field at equator to poles is 1:1.