Ratio of $\mathrm{\pi }$ bonds and $\sigma$ bonds in benzene molecule is

 The strongest chemical covalent bond that resulted from head-on overlapping of atomic orbitals. $\mathrm{\pi }$ bond The $\mathrm{\pi }$ bond, also referred to as a chemical covalent bond, is created by the laterally overlapping of two lobes from one atom's orbital with two lobes from another atom's orbital.

$\begin{array}{l}\text{no of }\mathrm{\pi }\text{ Bonds }(\mathrm{c}-\mathrm{c})=3\\ \text{no of }\mathrm{\sigma }\text{ Bonds }(\mathrm{c}-\mathrm{c})=6\\ \text{no of }\mathrm{\sigma }\text{ bonds }(\mathrm{c}-\mathrm{h})=6\\ \text{total }\mathrm{\sigma }\text{ bonds }=6+6=12\\ \text{ratio of }\mathrm{\pi }\text{ and }\mathrm{\sigma }=\frac{3}{12}=1:4\end{array}$

Therefore, the correct option is (A) $1:4$