Ravish wanted to make a temporary shelter for his car by making a box-like structure with a tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible. What should be the area of the tarpaulins required to make the shelter of height 2.5 m with base dimensions of $4 m × 3 m$ ?

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47m²

37m²

17m²

67m²

answer is A.

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Detailed Solution

Given the dimension of the base is

4 m × 3 m

, the height of shelter is 2.5m.
To find- tarpaulin required to make a shelter for the top and four sides.
Area of tarpaulin used =

2 l h + b h + l b

, where l is the length, b is the breadth and h is the height of the cube.
Length (l) = 4m
Breadth (b) = 3m
Height (h) = 2.5m
Area of tarpaulin used to make shelter for top and four sides

⇒ S A = 2 l h + b h + l b

⇒ S A = 2 [4 × 2.5 + 3 × 2.5] + 4 × 3

⇒ S A

= 47m².
Hence, the area of tarpaulin required to make the shelter of the height of 2.5m with given dimensions is 47m².
Hence, option 1 is the correct option.

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