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Rays from the sun converge at a point $15 cm$ in front of a concave mirror. Where should an object be placed so that the size of its image is equal to the size of the object?

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15 cm

in front of the mirror

30 cm

in front of the mirror

Between

15 cm and 30 cm

in front of the mirror

More than

30 cm

in front of the mirror

answer is B.

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Detailed Solution

The object should be placed

30 cm

in front of the mirror.
Given that rays from the sun converge at a point

15 cm

in front of a concave mirror. Since we know that the radius of curvature is double the focal length,

R = 2 \times f

Here, R is Radius of curvature and f is focal length.

R = 2 \times 15

R = 30 cm

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Rays from the sun converge at a point 15 cm in front of a concave mirror. Where should an object be placed so that the size of its image is equal to the size of the object?

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Rays from the sun converge at a point $15 cm$ in front of a concave mirror. Where should an object be placed so that the size of its image is equal to the size of the object?