Reaction -1:-  $\text{NaOH}+{\text{H}}_{\text{2}}\text{O}+{\text{P}}_{\text{4}} \to A+B\uparrow$      
Reaction -2:-  ${\text{F}}_{\text{2}} +\underset{Cold and dilute}{\text{NaOH}}\to \text{NaF}+ C\uparrow +D$ 
Reaction -3:-  $Si+NaOH+H_{2}O\to \text{\hspace{0.17em}\hspace{0.17em}}E+F\uparrow$

Which of the following is/are correct?

 Reaction -1 is disproportionation and hybridisation of central atom in B is $s{p}^3$

Reaction-2 is not disproportionation and bond angle of 'D' is greater than that of 'C' when both 'C' & 'D' are in gaseous phase

F is diamagnetic, and it reacts with the hardest alkali metal at 1073 K.

Bonds of anion of 'Z' are stronger & shorter compared to that of anion of Y.