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Reaction between the following pairs will produce $H_{2}$ except

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$Cu + {HCl}_{(aq .)}$

$Na +$ ethyl alcohol

$Fe +$ steam

$Fe + H_{2} {SO}_{4 (aq .)}$

answer is D.

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Detailed Solution

$Cu + HCl \to$ no reaction

Copper is less reactive than hydrogen. Therefore it is unable to displace hydrogen from acid.

$E_{C u}^{o} = + 0.34 and E_{H}^{o} = 0.00$

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