Reaction of chloroform with chlorine is an example of fraction order reaction. Its rate law expression is rate $= k [{CHCl}_{3}] {[{Cl}_{2}]}^{1 / 2}$ . If both are assumed in gaseous state and pressure is measured in bar then units of rate and rate constant respectively are

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$bar \min^{- 1}, {bar}^{- 1 / 2}, \min^{- 1}$

$bar \min^{- 1}, {bar}^{2} \min^{- 1}$

$bar \min^{- 1}, {bar}^{- 1 / 2}, \min^{- 1}$

${bar}^{- 1 / 2}, \min^{- 1}, {bar}^{2}, \min^{- 1}$

answer is B.

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Detailed Solution

Given, rate $= k [{CHCl}_{3}] {[{Cl}_{2}]}^{1 / 2}$
Order $= 1 + \frac{1}{2} = \frac{3}{2}$
So, units of rate constant $= \frac{Units of rate}{[{CHCl}_{3}] {[{Cl}_{2}]}^{1 / 2}} = \frac{bar \min^{- 1}}{{bar}^{3 / 2}}$
$= {bar}^{- 1 / 2} \min^{- 1}$
Units of rate is bar min^-1.