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Q.

Reaction of propanamide with ethanolic sodium hydroxide and bromine will give

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a

Propylamine

b

Aniline

c

Ethylamine

d

Methylamine

answer is B.

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Detailed Solution

$\underset{(Propanamide)}{{CH}_{3} {CH}_{2} {CONH}_{2}} \to_{{Br}_{2}}^{NaOH/Ethanol} \underset{(Ethylamine)}{{CH}_{3} {CH}_{2} {NH}_{2}}$

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Reaction of propanamide with ethanolic sodium hydroxide and bromine will give